*Question G5C09:
What is the capacitance of three 100-microfarad capacitors connected in series?*  

*Correct Answer is  C: 33.3 microfarads*  

### AI Response: (may contain errors)  

When capacitors are connected in series, the total capacitance ($C_{\text{total}}$) is less than any individual capacitor's capacitance. The formula for calculating the total capacitance of capacitors in series is:

$$
\frac{1}{C_{\text{total}}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} + \ldots
$$

For three capacitors, each with a capacitance of 100 microfarads, the formula becomes:

$$
\frac{1}{C_{\text{total}}} = \frac{1}{100} + \frac{1}{100} + \frac{1}{100}
$$

Simplifying the right side:

$$
\frac{1}{C_{\text{total}}} = \frac{3}{100}
$$

To find $C_{\text{total}}$, take the reciprocal:

$$
C_{\text{total}} = \frac{100}{3} \approx 33.3 \text{ microfarads}
$$

### Explanation of Choices:

- **A: 0.33 microfarads**  
  This is incorrect because it results from a misunderstanding of the series formula. The total capacitance is not this small.

- **B: 3.0 microfarads**  
  This is incorrect because it underestimates the total capacitance. The calculation does not support this value.

- **C: 33.3 microfarads**  
  This is correct. The calculation shows that the total capacitance of three 100-microfarad capacitors in series is approximately 33.3 microfarads.

- **D: 300 microfarads**  
  This is incorrect because it suggests a value larger than any individual capacitor, which is not possible in a series configuration.

By understanding the series capacitance formula, you can correctly determine that the total capacitance is 33.3 microfarads.