*Question G5C09:
What is the capacitance of three 100-microfarad capacitors connected in series?*  

*Correct Answer is  C: 33.3 microfarads*  

### AI Response: (may contain errors)  

To find the total capacitance of capacitors connected in series, we use the formula:

$$
\frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3}
$$

For three capacitors, each with a capacitance of $100 \, \mu F$ (microfarads), we can substitute the values:

$$
\frac{1}{C_{total}} = \frac{1}{100 \, \mu F} + \frac{1}{100 \, \mu F} + \frac{1}{100 \, \mu F}
$$

This simplifies to:

$$
\frac{1}{C_{total}} = \frac{3}{100 \, \mu F}
$$

To find $C_{total}$, we take the reciprocal:

$$
C_{total} = \frac{100 \, \mu F}{3} \approx 33.3 \, \mu F
$$

### Explanation of the Correct Answer:
- The correct answer is **33.3 microfarads** because when capacitors are connected in series, the total capacitance is less than the smallest individual capacitor. The calculation shows that the total capacitance is approximately $33.3 \, \mu F$.

### Explanation of Incorrect Choices:
- **A: 0.33 microfarads**: This value is too low and likely results from a misunderstanding of the series formula or a miscalculation.
- **B: 3.0 microfarads**: This value is also too low and does not reflect the correct application of the series capacitance formula.
- **D: 300 microfarads**: This value is too high and would be the result if the capacitors were in parallel, not in series.

### Summary:
- For capacitors in series, the total capacitance is calculated using the reciprocal formula.
- The correct answer is $33.3 \, \mu F$, while the other options do not apply to the series configuration.