*Question E7D13:
Which of the following calculates power dissipated by a series linear voltage regulator?*  

*Correct Answer is  C: Voltage difference from input to output multiplied by output current*  

### AI Response: (may contain errors)  

To calculate the power dissipated by a series linear voltage regulator, we need to understand how the regulator operates and how power is calculated in electrical circuits.

### Correct Answer: 
**C: Voltage difference from input to output multiplied by output current**

#### Explanation:
- The power dissipated by the regulator is due to the voltage drop across it when it regulates the input voltage down to the output voltage. 
- The formula for power ($P$) is given by:

$$
P = V \times I
$$

where:
- $V$ is the voltage across the component,
- $I$ is the current through the component.

In the case of a linear voltage regulator, the voltage difference ($V_{in} - V_{out}$) is the voltage drop across the regulator, and the current flowing through it is the output current ($I_{out}$). Therefore, the power dissipated can be expressed as:

$$
P_{dissipated} = (V_{in} - V_{out}) \times I_{out}
$$

### Why the Other Choices are Incorrect:

- **A: Input voltage multiplied by input current**  
  This choice calculates the total power supplied to the regulator, not the power dissipated. The input power does not account for the efficiency or losses in the regulator.

- **B: Input voltage divided by output current**  
  This choice does not represent any meaningful electrical quantity in this context. It does not relate to power dissipation and is not a valid formula for calculating power.

- **D: Output voltage multiplied by output current**  
  This choice calculates the output power delivered to the load, not the power dissipated by the regulator itself. While it is important to know the output power, it does not help in determining how much power is lost as heat in the regulator.

### Summary:
To find the power dissipated by a series linear voltage regulator, use the voltage difference from input to output multiplied by the output current. This reflects the energy lost as heat due to the voltage drop across the regulator.