*Question G5B12:
What is the RMS voltage across a 50-ohm dummy load dissipating 1200 watts?*  

*Correct Answer is  B: 245 volts*  

### AI Response: (may contain errors)  

To find the RMS voltage across a 50-ohm dummy load dissipating 1200 watts, we can use the formula for power in terms of voltage and resistance:

$$
P = \frac{V_{RMS}^2}{R}
$$

Where:
- $P$ = power in watts (1200 W)
- $V_{RMS}$ = RMS voltage in volts
- $R$ = resistance in ohms (50 ohms)

Rearranging the formula to solve for $V_{RMS}$ gives us:

$$
V_{RMS} = \sqrt{P \times R}
$$

Now, substituting the values:

$$
V_{RMS} = \sqrt{1200 \, \text{W} \times 50 \, \Omega} = \sqrt{60000} \approx 245 \, \text{V}
$$

### Explanation of the Correct Answer:
- The correct answer is **245 volts** because it is the calculated RMS voltage that corresponds to the given power and resistance using the formula above.

### Why the Other Choices are Incorrect:
- **A: 173 volts**
  - This value is too low. If we calculate the power using this voltage:
    $$ P = \frac{173^2}{50} \approx 600.58 \, \text{W} $$
    This is significantly less than 1200 W.

- **C: 346 volts**
  - This value is too high. Calculating the power:
    $$ P = \frac{346^2}{50} \approx 2401.76 \, \text{W} $$
    This exceeds the 1200 W specified.

- **D: 692 volts**
  - This value is also too high. The power calculation would be:
    $$ P = \frac{692^2}{50} \approx 9525.76 \, \text{W} $$
    This is far greater than 1200 W.

### Summary:
- The correct RMS voltage across a 50-ohm dummy load dissipating 1200 watts is **245 volts**.
- The other choices do not satisfy the power equation for the given load and power dissipation.