*Question G5B09:
What is the RMS voltage of a sine wave with a value of 17 volts peak?*  

*Correct Answer is  B: 12 volts*  

### AI Response: (may contain errors)  

To find the RMS (Root Mean Square) voltage of a sine wave, we use the formula:

$$
V_{RMS} = \frac{V_{peak}}{\sqrt{2}}
$$

where:
- $V_{RMS}$ = RMS voltage
- $V_{peak}$ = peak voltage

Given that the peak voltage ($V_{peak}$) is 17 volts, we can calculate the RMS voltage as follows:

$$
V_{RMS} = \frac{17 \text{ volts}}{\sqrt{2}} \approx \frac{17}{1.414} \approx 12 \text{ volts}
$$

### Explanation of the Correct Answer:
- The correct answer is **12 volts** because it is the result of applying the RMS formula to the given peak voltage of 17 volts.

### Explanation of Incorrect Choices:
- **A: 8.5 volts**: This value is half of the peak voltage, which is not how RMS is calculated for a sine wave.
  
- **C: 24 volts**: This value is double the peak voltage, which is incorrect. RMS is not simply a multiple of the peak voltage.
  
- **D: 34 volts**: This value is more than double the peak voltage and does not relate to the RMS calculation.

### Summary:
- The RMS voltage of a sine wave is always less than the peak voltage. For a sine wave, it is specifically calculated as the peak voltage divided by the square root of 2. Thus, for a peak voltage of 17 volts, the RMS voltage is approximately 12 volts.