*Question G9A09:
What standing wave ratio results from connecting a 50-ohm feed line to a 200-ohm resistive load?*  

*Correct Answer is  A: 4:1*  

### AI Response: (may contain errors)  

To determine the standing wave ratio (SWR) when connecting a 50-ohm feed line to a 200-ohm resistive load, we use the formula for SWR:

$$
\text{SWR} = \frac{R_L}{R_0} \quad \text{if } R_L > R_0
$$

where:
- $R_L$ = load resistance (200 ohms)
- $R_0$ = characteristic impedance of the feed line (50 ohms)

Substituting the given values:

$$
\text{SWR} = \frac{200}{50} = 4:1
$$

This calculation shows that the SWR is 4:1, which corresponds to choice A.

### Explanation of Other Choices:
- **B: 1:4**  
  This would imply the load resistance is less than the line impedance, which is not the case here.
  
- **C: 2:1**  
  This would occur if the load resistance were 100 ohms, not 200 ohms.
  
- **D: 1:2**  
  This is incorrect because it suggests the load resistance is less than the line impedance, which is not true in this scenario.

### Key Points:
- SWR is a measure of impedance matching between the feed line and the load.
- A higher SWR indicates a greater mismatch, leading to more reflected power.
- The SWR is always expressed as a ratio greater than or equal to 1:1.