*Question E7C02:
What is the frequency response of a T-network with series capacitors and a shunt inductor?*  

*Correct Answer is  B: High-pass*  

### AI Response: (may contain errors)  

To understand the frequency response of a T-network with series capacitors and a shunt inductor, let's break down the components and their effects:

1. **Series Capacitors**: Capacitors block DC and low-frequency signals while allowing high-frequency signals to pass. This characteristic is crucial in determining the network's response to different frequencies.

2. **Shunt Inductor**: An inductor in parallel (shunt) with the signal path will allow low-frequency signals to pass through it more easily, effectively shorting them to ground. However, it presents a high impedance to high-frequency signals, allowing them to continue through the network.

### Why the Correct Answer is High-pass:

- **High-pass Filter**: The combination of series capacitors and a shunt inductor creates a high-pass filter. The capacitors block low frequencies, and the inductor shunts them to ground, while high frequencies are allowed to pass through the network.

### Why the Other Choices are Incorrect:

- **Low-pass (Choice A)**: A low-pass filter would require the opposite configuration, typically with series inductors and shunt capacitors, allowing low frequencies to pass and blocking high frequencies.

- **Band-pass (Choice C)**: A band-pass filter allows a specific range of frequencies to pass while blocking frequencies outside this range. This requires a more complex arrangement of components, such as a combination of low-pass and high-pass elements.

- **Notch (Choice D)**: A notch filter is designed to block a specific narrow band of frequencies while allowing others to pass. This is not achieved with a simple T-network of series capacitors and a shunt inductor.

### Summary:

The T-network with series capacitors and a shunt inductor acts as a high-pass filter, allowing high-frequency signals to pass while blocking low-frequency signals. This is why the correct answer is **High-pass**.