*Question G5B13:
What is the output PEP of an unmodulated carrier if the average power is 1060 watts?*  

*Correct Answer is  B: 1060 watts*  

### AI Response: (may contain errors)  

To determine the output Peak Envelope Power (PEP) of an unmodulated carrier, it's important to understand that for an unmodulated carrier, the average power and the PEP are the same. This is because there are no variations in amplitude, as there would be with modulation.

1. **Correct Answer: 1060 watts**  
   - For an unmodulated carrier, the PEP is equal to the average power. Therefore, if the average power is 1060 watts, the PEP is also 1060 watts.

2. **Why the other choices are incorrect:**
   - **A: 530 watts**  
     - This choice is incorrect because it suggests the PEP is half of the average power, which is not true for an unmodulated carrier.
   - **C: 1500 watts**  
     - This choice is incorrect because it suggests the PEP is higher than the average power without any modulation, which is not the case.
   - **D: 2120 watts**  
     - This choice is incorrect because it implies the PEP is double the average power, which would only be true for a fully modulated AM signal, not an unmodulated carrier.

3. **Useful Rule of Thumb:**
   - For an unmodulated carrier, the PEP is equal to the average power:  
     $$ \text{PEP} = \text{Average Power} $$

This understanding is crucial for correctly answering questions about PEP in the context of unmodulated carriers.