*Question G8B07:
What is the frequency deviation for a 12.21 MHz reactance modulated oscillator in a 5 kHz deviation, 146.52 MHz FM phone transmitter?*  

*Correct Answer is  B: 416.7 Hz*  

### AI Response: (may contain errors)  

To determine the frequency deviation for a reactance modulated oscillator, we can use the following relationship:

$$
\Delta f = \frac{f_m}{f_c} \times \Delta f_c
$$

where:
- $\Delta f$ = frequency deviation of the modulated signal
- $f_m$ = frequency of the modulating signal
- $f_c$ = carrier frequency
- $\Delta f_c$ = maximum frequency deviation of the carrier

In this case:
- The modulating frequency $f_m = 12.21 \text{ MHz} = 12,210 \text{ kHz}$
- The carrier frequency $f_c = 146.52 \text{ MHz} = 146,520 \text{ kHz}$
- The maximum frequency deviation $\Delta f_c = 5 \text{ kHz}$

Now, we can calculate the frequency deviation:

1. Calculate the ratio of the modulating frequency to the carrier frequency:

$$
\frac{f_m}{f_c} = \frac{12,210}{146,520} \approx 0.0833
$$

2. Now, multiply this ratio by the maximum frequency deviation:

$$
\Delta f = 0.0833 \times 5 \text{ kHz} \approx 0.4167 \text{ kHz} = 416.7 \text{ Hz}
$$

Thus, the correct answer is **416.7 Hz**.

### Why the Other Choices are Incorrect:
- **A: 101.75 Hz**: This value does not correspond to any calculation based on the given parameters. It is too low compared to the calculated deviation.
- **C: 5 kHz**: This is the maximum frequency deviation of the carrier, not the frequency deviation resulting from the modulation.
- **D: 60 kHz**: This value is significantly higher than what we calculated and does not relate to the parameters provided.

### Summary:
- The frequency deviation for the given parameters is calculated to be **416.7 Hz**.
- The other choices do not match the calculations based on the relationship between the modulating frequency, carrier frequency, and maximum frequency deviation.