*Question G5C08:
What is the equivalent capacitance of two 5.0-nanofarad capacitors and one 750-picofarad capacitor connected in parallel?*  

*Correct Answer is  D: 10.750 nanofarads*  

### AI Response: (may contain errors)  

When capacitors are connected in parallel, their capacitances add up directly. The formula for the equivalent capacitance \( C_{\text{eq}} \) of capacitors in parallel is:

$$
C_{\text{eq}} = C_1 + C_2 + C_3 + \ldots
$$

In this problem, we have two 5.0-nanofarad capacitors and one 750-picofarad capacitor connected in parallel. First, we need to ensure all capacitances are in the same unit before adding them. Let's convert the 750-picofarad capacitor to nanofarads:

- 1 nanofarad (nF) = 1000 picofarads (pF)
- Therefore, 750 picofarads = 0.750 nanofarads

Now, add the capacitances:

- \( C_1 = 5.0 \) nanofarads
- \( C_2 = 5.0 \) nanofarads
- \( C_3 = 0.750 \) nanofarads

The equivalent capacitance is:

$$
C_{\text{eq}} = 5.0 + 5.0 + 0.750 = 10.750 \text{ nanofarads}
$$

### Explanation of Choices:

- **A: 576.9 nanofarads**  
  This choice is incorrect because it does not reflect the sum of the given capacitances in nanofarads.

- **B: 1,733 picofarads**  
  This choice is incorrect because it is not the correct conversion or sum of the given capacitances.

- **C: 3,583 picofarads**  
  This choice is incorrect because it does not match the sum of the capacitances when converted to picofarads or nanofarads.

- **D: 10.750 nanofarads**  
  This is the correct answer, as it accurately represents the sum of the capacitances in nanofarads.

By understanding how to add capacitances in parallel and converting units correctly, you can determine the equivalent capacitance accurately.