*Question G5B08:
What is the peak-to-peak voltage of a sine wave with an RMS voltage of 120 volts?*  

*Correct Answer is  D: 339.4 volts*  

### AI Response: (may contain errors)  

To find the peak-to-peak voltage of a sine wave given its RMS voltage, we can use the relationship between RMS voltage ($V_{RMS}$) and peak voltage ($V_{peak}$). The formula is:

$$
V_{peak} = V_{RMS} \times \sqrt{2}
$$

Once we have the peak voltage, the peak-to-peak voltage ($V_{pp}$) can be calculated as:

$$
V_{pp} = 2 \times V_{peak}
$$

### Step-by-step Calculation:

1. **Calculate the peak voltage**:
   Given $V_{RMS} = 120$ volts,
   $$ 
   V_{peak} = 120 \times \sqrt{2} \approx 120 \times 1.414 \approx 169.7 \text{ volts} 
   $$

2. **Calculate the peak-to-peak voltage**:
   $$ 
   V_{pp} = 2 \times 169.7 \approx 339.4 \text{ volts} 
   $$

### Explanation of the Correct Answer:
- The correct answer is **339.4 volts** because we correctly applied the formulas to convert the RMS voltage to peak voltage and then to peak-to-peak voltage.

### Why the Other Choices are Incorrect:
- **A: 84.8 volts**: This value does not correspond to any standard conversion from RMS to peak or peak-to-peak.
- **B: 169.7 volts**: This is the peak voltage, not the peak-to-peak voltage. It represents only half of what we need.
- **C: 240.0 volts**: This value does not match any calculations based on the given RMS voltage and is not derived from the correct formulas.

### Summary:
- To find the peak-to-peak voltage from an RMS voltage, use the formulas for peak voltage and then double it. For an RMS voltage of 120 volts, the peak-to-peak voltage is 339.4 volts.