*Question E7D13:
Which of the following calculates power dissipated by a series linear voltage regulator?*  

*Correct Answer is  C: Voltage difference from input to output multiplied by output current*  

### AI Response: (may contain errors)  

To calculate the power dissipated by a series linear voltage regulator, you need to consider the voltage drop across the regulator and the current flowing through it. The correct formula is:

$$
P_{\text{dissipated}} = (V_{\text{in}} - V_{\text{out}}) \times I_{\text{out}}
$$

where:
- $V_{\text{in}}$ = input voltage
- $V_{\text{out}}$ = output voltage
- $I_{\text{out}}$ = output current

### Explanation:

1. **Correct Answer (C): Voltage difference from input to output multiplied by output current**
   - The power dissipated by the regulator is due to the voltage drop across it, which is the difference between the input and output voltages, multiplied by the output current. This accounts for the energy lost as heat in the regulator.

2. **Why the other choices are incorrect:**
   - **Choice A: Input voltage multiplied by input current**
     - This would calculate the total power supplied to the regulator, not the power dissipated. It doesn't account for the output power.
   - **Choice B: Input voltage divided by output current**
     - This is not a valid formula for power. It doesn't relate to power dissipation in any meaningful way.
   - **Choice D: Output voltage multiplied by output current**
     - This calculates the power delivered to the load, not the power dissipated by the regulator itself.

### Key Points:
- Power dissipation in a linear regulator is primarily due to the voltage drop across it.
- The formula for power dissipation helps in understanding how much energy is lost as heat, which is crucial for thermal management in electronic circuits.