*Question G5C11:
What is the inductance of a circuit with a 20-millihenry inductor connected in series with a 50-millihenry inductor?*  

*Correct Answer is  C: 70 millihenries*  

### AI Response: (may contain errors)  

To find the total inductance of inductors connected in series, you simply add their inductances together. The formula for total inductance ($L_{total}$) in a series circuit is:

$$
L_{total} = L_1 + L_2
$$

where:
- $L_1$ = inductance of the first inductor
- $L_2$ = inductance of the second inductor

In this case, we have:
- $L_1 = 20 \text{ mH} = 20 \text{ millihenries}$
- $L_2 = 50 \text{ mH} = 50 \text{ millihenries}$

Now, substituting the values into the formula:

$$
L_{total} = 20 \text{ mH} + 50 \text{ mH} = 70 \text{ mH}
$$

Thus, the correct answer is **C: 70 millihenries**.

### Explanation of Other Choices:
- **A: 7 millihenries**: This is incorrect because it does not reflect the addition of the two inductors. It seems to be a miscalculation or misunderstanding of the series addition rule.
  
- **B: 14.3 millihenries**: This is also incorrect. It may arise from a misunderstanding of how to combine inductances or a miscalculation.
  
- **D: 1,000 millihenries**: This is incorrect as it is far too high. It may be a result of confusing millihenries with henries or a simple arithmetic error.

### Summary:
- For inductors in series, always add their inductances directly.
- The total inductance for this example is $70$ millihenries, confirming that the correct answer is **C: 70 millihenries**.