*Question G5C08:
What is the equivalent capacitance of two 5.0-nanofarad capacitors and one 750-picofarad capacitor connected in parallel?*  

*Correct Answer is  D: 10.750 nanofarads*  

### AI Response: (may contain errors)  

To find the equivalent capacitance of capacitors connected in parallel, you simply add their capacitances together. The formula for total capacitance ($C_{total}$) in a parallel circuit is:

$$
C_{total} = C_1 + C_2 + C_3 + \ldots
$$

In this case, we have two capacitors of 5.0 nanofarads (nF) and one capacitor of 750 picofarads (pF). First, we need to convert all capacitances to the same unit. 

1. **Convert 750 pF to nF:**
   - Since $1 \text{ nF} = 1,000 \text{ pF}$, we convert:
   $$
   750 \text{ pF} = \frac{750}{1000} \text{ nF} = 0.75 \text{ nF}
   $$

2. **Add the capacitances:**
   - Now we can add the capacitances:
   $$
   C_{total} = 5.0 \text{ nF} + 5.0 \text{ nF} + 0.75 \text{ nF} = 10.75 \text{ nF}
   $$

Thus, the equivalent capacitance is **10.750 nanofarads**, which corresponds to choice D.

### Explanation of Choices:
- **Choice A: 576.9 nanofarads**
  - Incorrect because it does not reflect the correct addition of the given capacitances.
  
- **Choice B: 1,733 picofarads**
  - Incorrect as it is a miscalculation of the total capacitance in picofarads. The correct total in picofarads is $10.75 \text{ nF} = 10,750 \text{ pF}$.

- **Choice C: 3,583 picofarads**
  - Incorrect for the same reason as choice B; it does not represent the correct total capacitance.

### Summary:
- The correct answer is **10.750 nanofarads** because we correctly added the capacitances of the two 5.0 nF capacitors and the converted 750 pF capacitor.
- Remember, for capacitors in parallel, always add their capacitances directly.