*Question T4A03:
Why are short, heavy-gauge wires used for a transceiver’s DC power connection?*  

*Correct Answer is  A: To minimize voltage drop when transmitting*  

### AI Response: (may contain errors)  

To understand why short, heavy-gauge wires are used for a transceiver’s DC power connection, let's analyze the correct answer and the other choices.

### Correct Answer: A - To minimize voltage drop when transmitting

- **Explanation**: 
  - Heavy-gauge wires have a lower resistance compared to thinner wires. When current flows through a wire, there is a voltage drop due to the wire's resistance, described by Ohm's Law:
  
  $$V_{drop} = I \times R$$
  
  where:
  - $V_{drop}$ = voltage drop across the wire
  - $I$ = current flowing through the wire
  - $R$ = resistance of the wire
  
  - Using short wires also helps reduce the total resistance, further minimizing the voltage drop. This is crucial during transmission when the transceiver requires sufficient voltage to operate effectively.

### Why the Other Choices are Incorrect:

- **B: To provide a good counterpoise for the antenna**  
  - **Explanation**: 
    - A counterpoise is typically a ground or a reflective surface for antennas, not related to the DC power connection. The wires used for power do not serve this purpose.

- **C: To avoid RF interference**  
  - **Explanation**: 
    - While using proper wiring can help reduce interference, the primary reason for using short, heavy-gauge wires is to minimize voltage drop. RF interference is more related to the design of the circuit and shielding rather than the gauge of the power wires.

- **D: All these choices are correct**  
  - **Explanation**: 
    - Since choices B and C are incorrect, this option cannot be correct either.

### Summary

- **Key Takeaway**: Use short, heavy-gauge wires for DC power connections to minimize voltage drop, ensuring the transceiver operates efficiently during transmission.