*Question G5C07:
What transformer turns ratio matches an antenna’s 600-ohm feed point impedance to a 50-ohm coaxial cable?*  

*Correct Answer is  A: 3.5 to 1*  

### AI Response: (may contain errors)  

To match a 600-ohm antenna feed point impedance to a 50-ohm coaxial cable, we need to determine the appropriate transformer turns ratio. The formula for calculating the turns ratio ($N$) for impedance matching is:

$$
N = \sqrt{\frac{Z_{primary}}{Z_{secondary}}}
$$

Where:
- $Z_{primary}$ = impedance of the antenna (600 ohms)
- $Z_{secondary}$ = impedance of the coaxial cable (50 ohms)

Substituting the values into the formula:

$$
N = \sqrt{\frac{600}{50}} = \sqrt{12} \approx 3.46
$$

This rounds to approximately 3.5, which corresponds to the correct answer:

**Correct Answer: 3.5 to 1**

### Explanation of the Correct Answer:
- The turns ratio of 3.5 to 1 means that for every 3.5 turns on the primary side (connected to the 600-ohm antenna), there is 1 turn on the secondary side (connected to the 50-ohm coax). This ratio effectively transforms the impedance from 600 ohms to 50 ohms, allowing for efficient power transfer.

### Why the Other Choices are Incorrect:
- **A: 12 to 1**  
  This would imply a much larger impedance transformation, which is not needed for matching 600 ohms to 50 ohms.

- **B: 24 to 1**  
  This ratio would transform 50 ohms to 1200 ohms, which is far too high for our application.

- **C: 144 to 1**  
  This would transform 50 ohms to 7200 ohms, which is excessive and not suitable for matching to a 600-ohm load.

### Summary:
- The correct turns ratio to match a 600-ohm feed point to a 50-ohm coaxial cable is approximately 3.5 to 1.
- Use the formula for turns ratio to determine the appropriate matching for different impedance levels.