*Question G5B13:
What is the output PEP of an unmodulated carrier if the average power is 1060 watts?*  

*Correct Answer is  B: 1060 watts*  

### AI Response: (may contain errors)  

To determine the output Peak Envelope Power (PEP) of an unmodulated carrier when the average power is given, we can use the following understanding:

1. **Understanding Average Power and PEP**:
   - For an unmodulated carrier, the average power is equal to the PEP. This is because, in the case of an unmodulated signal, the power does not vary over time; it remains constant.

Thus, we have:
$$
PEP = P_{avg}
$$
where:
- $PEP$ = Peak Envelope Power
- $P_{avg}$ = Average Power

2. **Correct Answer**:
   - Since the average power is given as 1060 watts, the PEP is also 1060 watts. Therefore, the correct answer is **B: 1060 watts**.

3. **Why Other Choices Are Incorrect**:
   - **A: 530 watts**: This value does not represent the PEP for an unmodulated carrier; it is less than the average power.
   - **C: 1500 watts**: This value is higher than the average power and does not apply to an unmodulated carrier.
   - **D: 2120 watts**: This value is also higher than the average power and is not applicable.

In summary, for an unmodulated carrier, the average power and PEP are the same, which is why the correct answer is 1060 watts.