*Question G5B09:
What is the RMS voltage of a sine wave with a value of 17 volts peak?*  

*Correct Answer is  B: 12 volts*  

### AI Response: (may contain errors)  

To find the RMS (Root Mean Square) voltage of a sine wave, you can use the formula:

$$
V_{\text{RMS}} = \frac{V_{\text{peak}}}{\sqrt{2}}
$$

where:
- $V_{\text{RMS}}$ is the RMS voltage.
- $V_{\text{peak}}$ is the peak voltage.

Given that the peak voltage $V_{\text{peak}}$ is 17 volts, we can calculate the RMS voltage as follows:

$$
V_{\text{RMS}} = \frac{17}{\sqrt{2}} \approx 12 \text{ volts}
$$

**Explanation of the Correct Answer:**

- **12 volts (Choice B):** This is the correct answer because it is the result of dividing the peak voltage by $\sqrt{2}$, which is the standard method for converting peak voltage to RMS voltage for a sine wave.

**Explanation of Incorrect Choices:**

- **8.5 volts (Choice A):** This value is half of the peak voltage, which is not the correct method for calculating RMS voltage. It might be confused with the peak-to-peak voltage divided by 2, but that is not applicable here.

- **24 volts (Choice C):** This value is greater than the peak voltage, which is not possible for RMS voltage. RMS voltage is always less than or equal to the peak voltage for a sine wave.

- **34 volts (Choice D):** This value is double the peak voltage, which is incorrect. It might be confused with peak-to-peak voltage, but RMS voltage is not calculated this way.

Remember, for a sine wave, the RMS voltage is always the peak voltage divided by $\sqrt{2}$.