*Question G5B05:
How many watts are consumed when a current of 7.0 milliamperes flows through a 1,250-ohm resistance?*  

*Correct Answer is  A: Approximately 61 milliwatts*  

### AI Response: (may contain errors)  

To determine the power consumed in a resistor, we use the formula for electrical power:

$$
P = I^2 \times R
$$

where:
- $P$ is the power in watts,
- $I$ is the current in amperes,
- $R$ is the resistance in ohms.

Given:
- Current, $I = 7.0$ milliamperes = $7.0 \times 10^{-3}$ amperes,
- Resistance, $R = 1,250$ ohms.

Substitute these values into the formula:

$$
P = (7.0 \times 10^{-3})^2 \times 1,250
$$

Calculate the power:

1. Calculate the square of the current:
   $$ (7.0 \times 10^{-3})^2 = 49 \times 10^{-6} = 0.000049 $$
2. Multiply by the resistance:
   $$ P = 0.000049 \times 1,250 = 0.06125 \text{ watts} $$

Convert watts to milliwatts (1 watt = 1,000 milliwatts):

$$
P = 0.06125 \times 1,000 = 61.25 \text{ milliwatts}
$$

Thus, the correct answer is approximately 61 milliwatts.

**Explanation of Choices:**

- **A: Approximately 61 milliwatts**  
  This is correct as calculated above.

- **B: Approximately 61 watts**  
  Incorrect. This is 1,000 times too large because it does not account for the conversion from milliwatts to watts.

- **C: Approximately 11 milliwatts**  
  Incorrect. This is too low because it results from an incorrect calculation of power.

- **D: Approximately 11 watts**  
  Incorrect. This is also too high and results from a misunderstanding of the conversion between milliwatts and watts.

By using the power formula and converting units correctly, we find that the power consumed is approximately 61 milliwatts.