Question E1A06:
[97.303(h)(1)] What is the required transmit frequency of a CW signal for channelized 60 meter operation?  

Choices:  
A: At the lowest frequency of the channel  
B: At the center frequency of the channel  
C: At the highest frequency of the channel  
D: On any frequency where the signal’s sidebands are within the channel    

Correct Answer is  B: At the center frequency of the channel  

To operate CW on the 60-meter channels, FCC Part 97.303(h)(1) requires your transmitted carrier to be on the channel center frequency.

Why the correct answer is correct:
- 60 meters is channelized. For CW, the rule is to transmit at the channel center so the emission is centered within the channel.
- In shorthand: $$f_{CW} = f_c$$ where $f_c$ is the published channel center frequency.

Why the other choices are incorrect:
- A: “Lowest frequency of the channel” — This would place your CW carrier at the lower edge, risking out-of-channel energy and violating the centering requirement.
- C: “Highest frequency of the channel” — Same issue at the upper edge; not permitted.
- D: “Any frequency where the signal’s sidebands are within the channel” — Not allowed on 60 m; the rule explicitly requires centering. Also, CW isn’t managed like SSB audio sidebands on this band.

Useful rules of thumb:
- 60 m uses specific channel centers (e.g., 5330.5, 5346.5, 5357.0, 5371.5, 5403.5 kHz in the US).
- CW: transmit on the center frequency: $$f_{TX} = f_c$$
- USB phone (for contrast): set the dial 1.5 kHz below center so the voice occupies the channel properly: $$f_{dial} = f_c - 1.5\ \text{kHz}$$

Exam tip: For CW on 60 m, “center frequency” is the required transmit frequency.