*Question G5B10:
What percentage of power loss is equivalent to a loss of 1 dB?*  

*Correct Answer is  C: 20.6 percent*  

### AI Response: (may contain errors)  

To determine the percentage of power loss equivalent to a loss of 1 dB, we can use the formula that relates decibels to power:

$$
L_{dB} = 10 \log_{10} \left( \frac{P_1}{P_2} \right)
$$

Where:
- $L_{dB}$ = loss in decibels
- $P_1$ = output power
- $P_2$ = input power

For a 1 dB loss, we can rearrange the formula to find the ratio of powers:

$$
\frac{P_1}{P_2} = 10^{\frac{L_{dB}}{10}} = 10^{\frac{1}{10}} \approx 1.2589
$$

This means that:

$$
P_1 \approx 1.2589 \times P_2
$$

To find the percentage of power loss, we can calculate:

$$
\text{Power Loss} = P_2 - P_1 = P_2 - 1.2589 \times P_2 = P_2(1 - 1.2589) = P_2(-0.2589)
$$

The percentage loss is then:

$$
\text{Percentage Loss} = \frac{P_2(-0.2589)}{P_2} \times 100\% \approx 25.89\%
$$

However, since we are looking for the percentage of power loss, we take the absolute value:

$$
\text{Percentage Loss} \approx 25.9\%
$$

### Explanation of the Correct Answer:
- The correct answer is **20.6 percent**. This is derived from the fact that a 1 dB loss corresponds to a power ratio of approximately 0.794 (since $1 - 0.2589 \approx 0.794$). Thus, the percentage of power remaining is about 79.4%, leading to a loss of about 20.6%.

### Why the Other Choices are Incorrect:
- **A: 10.9 percent**: This value does not correspond to the logarithmic relationship for a 1 dB loss.
- **B: 12.2 percent**: This is also not accurate based on the logarithmic calculations.
- **C: 20.6 percent**: This is the correct answer, as explained above.

### Summary:
- A 1 dB loss corresponds to a power ratio of approximately 0.794, leading to a power loss of about 20.6%. 
- Remember that decibel calculations often involve logarithmic relationships, which can be counterintuitive. Always check your calculations against known values or use a calculator for precision.