*Question G5B03:
How many watts of electrical power are consumed if 400 VDC is supplied to an 800-ohm load?*  

*Correct Answer is  B: 200 watts*  

### AI Response: (may contain errors)  

To determine the power consumed by a load, we can use the formula for electrical power:

$$
P = \frac{V^2}{R}
$$

where:
- $P$ = power in watts
- $V$ = voltage in volts
- $R$ = resistance in ohms

In this case, we have:
- $V = 400 \, \text{VDC}$
- $R = 800 \, \Omega$

Now, substituting the values into the formula:

$$
P = \frac{400^2}{800}
$$

Calculating $400^2$ gives us $160000$. Now, we divide by $800$:

$$
P = \frac{160000}{800} = 200 \, \text{watts}
$$

### Explanation of the Correct Answer:
- The correct answer is **200 watts** because we applied the power formula correctly with the given voltage and resistance values.

### Explanation of Incorrect Choices:
- **A: 0.5 watts**: This value is too low and does not reflect the calculations based on the given voltage and resistance.
- **B: 200 watts**: This is the correct answer, as shown in the calculations.
- **C: 400 watts**: This value would imply a different relationship between voltage and resistance, which does not apply here.
- **D: 3200 watts**: This value is incorrect as it suggests a much higher power consumption than calculated.

### Summary:
- Use the formula $P = \frac{V^2}{R}$ to find power.
- For this problem, substituting the values gives us the correct power consumption of **200 watts**.