*Question G5B11:
What is the ratio of PEP to average power for an unmodulated carrier?*  

*Correct Answer is  B: 1.00*  

### AI Response: (may contain errors)  

For an unmodulated carrier, the Peak Envelope Power (PEP) is equal to the average power. This is because an unmodulated carrier is a continuous wave (CW) signal with a constant amplitude. Therefore, there are no variations in the signal's amplitude over time, and the peak power is the same as the average power.

### Explanation:

1. **Correct Answer (B: 1.00):**
   - For an unmodulated carrier, the power does not vary with time. Thus, the peak power (PEP) is the same as the average power.
   - The ratio of PEP to average power is:
     $$\text{Ratio} = \frac{\text{PEP}}{\text{Average Power}} = \frac{P}{P} = 1.00$$

2. **Incorrect Choices:**
   - **A: 0.707**: This value is related to the RMS (Root Mean Square) value of a sine wave, not the ratio of PEP to average power.
   - **C: 1.414**: This is the reciprocal of 0.707 and is also related to RMS calculations, not applicable here.
   - **D: 2.00**: This would imply that the peak power is twice the average power, which is not the case for an unmodulated carrier.

### Key Points:
- **Unmodulated Carrier**: A constant amplitude signal where PEP equals average power.
- **PEP to Average Power Ratio**: For an unmodulated carrier, this ratio is always 1.00.