*Question G5C10:
What is the inductance of three 10-millihenry inductors connected in parallel?*  

*Correct Answer is  C: 3.3 millihenries*  

### AI Response: (may contain errors)  

To find the total inductance of inductors connected in parallel, we use the formula:

$$
\frac{1}{L_{total}} = \frac{1}{L_1} + \frac{1}{L_2} + \frac{1}{L_3}
$$

For three inductors of equal inductance $L$ (in this case, 10 millihenries or 0.01 henries), the formula simplifies to:

$$
\frac{1}{L_{total}} = \frac{1}{0.01} + \frac{1}{0.01} + \frac{1}{0.01} = \frac{3}{0.01} = 300
$$

Now, taking the reciprocal to find $L_{total}$:

$$
L_{total} = \frac{1}{300} \approx 0.00333 \text{ henries} = 3.3 \text{ millihenries}
$$

### Explanation of the Correct Answer:
- The correct answer is **3.3 millihenries** because when three inductors of 10 millihenries are connected in parallel, their total inductance is reduced, resulting in a lower value than any individual inductor.

### Why the Other Choices are Incorrect:
- **A: 0.30 henries**: This value is too high. It suggests a total inductance that would occur if the inductors were in series, not parallel.
- **B: 3.3 henries**: This value is also too high and does not reflect the parallel configuration.
- **D: 30 millihenries**: This value is too high as well; it would be the result of adding inductances in series, not parallel.

### Summary:
- For inductors in parallel, the total inductance is always less than the smallest individual inductor.
- The formula for total inductance in parallel is crucial for calculating the effective inductance in such configurations.