*Question G5B14:
What is the output PEP of 500 volts peak-to-peak across a 50-ohm load?*  

*Correct Answer is  B: 625 watts*  

### AI Response: (may contain errors)  

To find the output Peak Envelope Power (PEP) given a peak-to-peak voltage across a load, you can use the following steps:

1. **Convert Peak-to-Peak Voltage to RMS Voltage:**

   The RMS (Root Mean Square) voltage is calculated from the peak voltage, not the peak-to-peak voltage. First, find the peak voltage by dividing the peak-to-peak voltage by 2:

   $$ V_{\text{peak}} = \frac{V_{\text{p-p}}}{2} = \frac{500 \, \text{V}}{2} = 250 \, \text{V} $$

   Then, convert the peak voltage to RMS voltage:

   $$ V_{\text{RMS}} = \frac{V_{\text{peak}}}{\sqrt{2}} = \frac{250 \, \text{V}}{\sqrt{2}} \approx 176.78 \, \text{V} $$

2. **Calculate the Power using the RMS Voltage:**

   The power across a resistive load can be calculated using the formula:

   $$ P = \frac{V_{\text{RMS}}^2}{R} $$

   where:
   - $V_{\text{RMS}}$ is the RMS voltage
   - $R$ is the resistance (50 ohms in this case)

   Plug in the values:

   $$ P = \frac{(176.78 \, \text{V})^2}{50 \, \Omega} \approx 625 \, \text{W} $$

Therefore, the correct answer is 625 watts.

### Why the Other Choices are Incorrect:

- **Choice A: 8.75 watts**  
  This value is far too low for the given voltage and load resistance. It might result from a miscalculation or misunderstanding of the formula.

- **Choice C: 2500 watts**  
  This value is too high. It could result from incorrectly using the peak voltage instead of the RMS voltage in the power formula.

- **Choice D: 5000 watts**  
  This is also too high and likely results from a similar mistake as in Choice C, possibly using the peak-to-peak voltage directly in the power formula without proper conversion.

By following the correct steps and using the appropriate formulas, you can accurately determine the PEP for the given conditions.