*Question G5B11:
What is the ratio of PEP to average power for an unmodulated carrier?*  

*Correct Answer is  B: 1.00*  

### AI Response: (may contain errors)  

To understand the ratio of Peak Envelope Power (PEP) to average power for an unmodulated carrier, we need to consider the definitions of these terms:

- **Peak Envelope Power (PEP)**: This is the maximum power level of a signal during its peak amplitude.
- **Average Power**: This is the average power delivered over a period of time.

For an unmodulated carrier, the power remains constant, meaning that the peak power and the average power are the same. Therefore, the ratio of PEP to average power is:

$$
\text{Ratio} = \frac{PEP}{\text{Average Power}} = \frac{P}{P} = 1.00
$$

### Explanation of the Correct Answer:
- **Correct Answer: 1.00**  
  This is correct because, for an unmodulated carrier, the peak power and average power are equal. Thus, the ratio is 1.

### Explanation of Incorrect Choices:
- **A: 0.707**  
  This value is often associated with the relationship between peak and average power for a sinusoidal waveform with modulation, not for an unmodulated carrier.

- **C: 1.414**  
  This value is the square root of 2, which is relevant in certain modulation schemes but does not apply to an unmodulated carrier.

- **D: 2.00**  
  This value does not apply to any standard relationship between PEP and average power for an unmodulated carrier.

### Summary:
- For an unmodulated carrier, the PEP equals the average power, leading to a ratio of 1.00.
- The other choices reflect relationships that apply to modulated signals or different contexts, not to an unmodulated carrier.

This understanding is crucial for the Extra Class exam, as it highlights the fundamental concepts of power in radio communications.