*Question G5B06:
What is the PEP produced by 200 volts peak-to-peak across a 50-ohm dummy load?*  

*Correct Answer is  B: 100 watts*  

### AI Response: (may contain errors)  

To calculate the Peak Envelope Power (PEP) produced by a voltage across a load, we can use the following formula:

$$
PEP = \frac{V_{pp}^2}{2R}
$$

where:
- $V_{pp}$ = peak-to-peak voltage
- $R$ = load resistance in ohms

### Step-by-step Calculation:

1. **Convert Peak-to-Peak Voltage to RMS Voltage**:
   The peak-to-peak voltage ($V_{pp}$) is given as 200 volts. To find the RMS voltage ($V_{rms}$), we use the relationship:

   $$
   V_{rms} = \frac{V_{pp}}{2\sqrt{2}} = \frac{200}{2\sqrt{2}} \approx 70.71 \text{ volts}
   $$

2. **Calculate PEP**:
   Now, substituting $V_{pp}$ and $R$ into the PEP formula:

   $$
   PEP = \frac{200^2}{2 \times 50} = \frac{40000}{100} = 400 \text{ watts}
   $$

However, this is the total power calculation. To find the average power, we need to consider the effective power delivered to the load, which is:

$$
P = \frac{V_{rms}^2}{R} = \frac{(70.71)^2}{50} \approx 100 \text{ watts}
$$

### Explanation of the Correct Answer:
- The correct answer is **100 watts** because it represents the average power delivered to the 50-ohm dummy load when the peak-to-peak voltage is 200 volts.

### Why the Other Choices are Incorrect:
- **Choice A: 1.4 watts**: This value is too low and does not reflect the calculations based on the given voltage and resistance.
- **Choice C: 353.5 watts**: This value does not correspond to any standard calculation for PEP or average power based on the provided voltage and load.
- **Choice D: 400 watts**: This value represents the peak power calculation but does not account for the average power delivered to the load, which is what we are looking for in this context.

### Summary:
- Use the formula for PEP and remember to convert peak-to-peak voltage to RMS when calculating average power.
- The average power delivered to a 50-ohm load with a 200-volt peak-to-peak signal is **100 watts**.